正确答案: C

标准ACL可以根据分组中的IP目标地址进行过滤

题目:访问控制列表分为标准和扩展两种。下面关于ACL的描述中,错误的是()。

解析:C

查看原题

举一反三的答案和解析:

  • [单选题]标准访问控制列表应被放置的最佳位置是在()。
  • 越靠近数据包的目的地越好


  • [多选题]CDP is being used throughout the Ezonexam network. What are two reasons why the Ezonexam network administrator would use CDP? (Choose two)
  • To obtain the IP Address of a connected device in order to telnet to the device

    To verify Layer 2 connectivity between two devices when Layer 3 fails


  • [单选题]Study the Exhibit below carefully:London#show vtp
  • Forwards information about VTP configuration.

  • 解析:解析:Explanation:FromtheoutputthisswitchisoperatingmerelyasVTPclient,soitbasicallydoesastheVTPserversays,andpassesoninformationaboutVTPconfigurationtothenextswitchinline.IncorrectAnswers:A.Thisisincorrectbecausethefunctionisredundant.B.ThisincorrectbecausetheswitchmustbeinserverortransparentmodetocreateandchangeVLANs.D.ThisisincorrectbecauseifVTPwouldbedisabled,itwouldn'tappearonthecommandoutput.E.Ifthisweretrue,theVTPconfigurationinformationwouldnotbedisplayedafterbeingpoweredon.

  • [单选题]IP地址为:192.168.50.70,掩码为:255.255.255.248,则该IP和掩码结合,共划分了多少个子网(不包括全0子网和全1子网)()
  • 30


  • [单选题]路由器上的命令“show version”的功能是()
  • 显示版本信息


  • [单选题]The IP network 210.106.14.0 is subnetted using a /24 mask. How many usable networks and host addresses can be obtained from this?
  • 1 network with 254 hosts

  • 解析:解析:Explanation:Asubnetwith24bitsonwouldbe255.255.255.0.SincethisisaclassCnetwork,thissubnetcanhaveonly1networkand254usablehosts.

  • [单选题]TCP23是()协议端口号;UDP69是()端口号;TCP80是()端口号。
  • TELNET TFTP HTTP


  • [单选题]How many usable IP addresses can you get from a conventional Class C address?
  • 254

  • 解析:解析:Explanation:

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