1. [多选题]The Ezonexam network administrator wants to ensure that only a single web server can connect to pot Fa0/1 on a catalyst switch. The server is plugged into the switch's Fast Eth. 0/1 port and the network administrator is about to bring the server online. What can the administrator do to ensure that only the MAC address of this server is allowed by switch port Fa0/1? (Choose two)
A. Configure port Fa0/1 to accept connections only from the static IP address of the server
B. Configure the MAC address of the server as a static entry associated with port Fa0/1
C. Employ a proprietary connector type on Fa0/1 that is incomputable with other host connectors
D. Configure port security on Fa0/1 to reject traffic with a source MAC address other than that of the server
E. Bind the IP address of the server to its MAC address on the switch to prevent other hosts from spoofing the server IP address
2. [单选题]You are an administrator of the Ezonexam switched network and your goal is to reduce some of the administrative overhead on your network. You plan on achieving this by configuring a new VLAN for each department in the Ezonexam network.However, you need to share the VLAN information across numerous switches. Which of the following would allow you accomplish this?
A. STP
B. GVRP
C. SNMP
D. VTP
E. DHCP
F. F. None of the above
3. [单选题]IP地址为:192.168.50.70,掩码为:255.255.255.248,则该IP和掩码结合,共划分了多少个子网(不包括全0子网和全1子网)()
A. 8
B. 30
C. 6
D. 14
4. [单选题]下列哪个network命令会告知此路由器开始使用IP地址为10.1.1.1、10.1.100.1和10.1.120.1的接口上的OSPF()
A. network 10.0.0.0 255.0.0.0 area 0
B. network 10.0.0.0 0.255.255.255 area 0
C. network 10.0.0.1 0.0.0.255 area 0
D. network 10.0.0.1 0.0.255.255 area 0
5. [单选题]The Ezonexam network administrator has just issued the "switchport trunk native vlan 998" command on switch VE2. What is the function of this command?
A. It designates VLAN 998 as the default for all unknown tagged traffic
B. It designates VLAN 998 for untagged traffic
C. It blocks VLAN 998 traffic from passing on the trunk
D. It creates a VLAN 998 interface
E. None of the above